@cm0002@lemmy.world to Comic Strips@lemmy.world • 2 months agoPerfectly balanced, as all things should be.lemmy.mlimagemessage-square15fedilinkarrow-up1464arrow-down111cross-posted to: comics@lemmy.ml
arrow-up1453arrow-down1imagePerfectly balanced, as all things should be.lemmy.ml@cm0002@lemmy.world to Comic Strips@lemmy.world • 2 months agomessage-square15fedilinkcross-posted to: comics@lemmy.ml
minus-square@CompassRed@discuss.tchncs.delinkfedilink2•2 months agoInteresting. I think it isn’t unital either otherwise Ω=0. 0=Ω+Ω=Ω+ΩΩ=Ω(1+Ω)=ΩΩ=Ω
minus-square@Leate_Wonceslace@lemmy.dbzer0.comlinkfedilinkEnglish1•11 days agoSomeone else had the same observation, but it is unital. Keep in mind that it isn’t associative; you can’t pull out the Omega like that.
minus-square@CompassRed@discuss.tchncs.delinkfedilink1•10 days agoThe definition I’m aware of for non associative algebras has them distributive by default, so I believe the chain of equations is valid.
Interesting. I think it isn’t unital either otherwise Ω=0.
0=Ω+Ω=Ω+ΩΩ=Ω(1+Ω)=ΩΩ=Ω
Someone else had the same observation, but it is unital. Keep in mind that it isn’t associative; you can’t pull out the Omega like that.
The definition I’m aware of for non associative algebras has them distributive by default, so I believe the chain of equations is valid.